Ds\Set::xor

(PECL ds >= 1.0.0)

Ds\Set::xor — Creates a new set using values in either the current instance or in another set, but not in both

说明

public Ds\Set::xor ( Ds\Set $set ) : Ds\Set

Creates a new set containing values in the current instance as well as another set, but not in both.

A ? B = {x : x ∈ (A \ B) ∪ (B \ A)}

参数

set

The other set.

返回值

A new set containing values in the current instance as well as another set, but not in both.

See Also

范例

Example #1 Ds\Set::xor() example

<?php
$a = new \Ds\Set([1, 2, 3]);
$b = new \Ds\Set([3, 4, 5]);

var_dump($a->xor($b));
?>

以上例程的输出类似于：

object(Ds\Set)#3 (4) {
  [0]=>
  int(1)
  [1]=>
  int(2)
  [2]=>
  int(4)
  [3]=>
  int(5)
}